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1100043413 = 7478094133
BaseRepresentation
bin100000110010001…
…0101010010010101
32211122220222212122
41001210111102111
54223102342123
6301053425325
736155133440
oct10144252225
92748828778
101100043413
11514a44997
1226849b245
13146b97681
14a6150657
1566893bc8
hex41915495

1100043413 has 16 divisors (see below), whose sum is σ = 1285839360. Its totient is φ = 921469056.

The previous prime is 1100043409. The next prime is 1100043421. The reversal of 1100043413 is 3143400011.

It is a cyclic number.

It is not a de Polignac number, because 1100043413 - 22 = 1100043409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100043391 and 1100043400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100043443) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 264095 + ... + 268227.

It is an arithmetic number, because the mean of its divisors is an integer number (80364960).

Almost surely, 21100043413 is an apocalyptic number.

It is an amenable number.

1100043413 is a deficient number, since it is larger than the sum of its proper divisors (185795947).

1100043413 is an equidigital number, since it uses as much as digits as its factorization.

1100043413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4996.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1100043413 is about 33166.9023726968. The cubic root of 1100043413 is about 1032.2936953919.

Adding to 1100043413 its reverse (3143400011), we get a palindrome (4243443424).

The spelling of 1100043413 in words is "one billion, one hundred million, forty-three thousand, four hundred thirteen".

Divisors: 1 7 47 329 809 4133 5663 28931 38023 194251 266161 1359757 3343597 23405179 157149059 1100043413