1100050117 has 2 divisors, whose sum is σ = 1100050118. Its totient is φ = 1100050116.

The previous prime is 1100050111. The next prime is 1100050169. The reversal of 1100050117 is 7110500011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 964350916 + 135699201 = 31054^2 + 11649^2 .

It is an emirp because it is prime and its reverse (7110500011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100050117 - 2³ = 1100050109 is a prime.

It is a super-2 number, since 2×1100050117² = 2420220519823427378, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1100050117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100050111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550025058 + 550025059.

It is an arithmetic number, because the mean of its divisors is an integer number (550025059).

Almost surely, 2^1100050117 is an apocalyptic number.

It is an amenable number.

1100050117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100050117 is an equidigital number, since it uses as much as digits as its factorization.

1100050117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 35, while the sum is 16.

The square root of 1100050117 is about 33167.0034371512. The cubic root of 1100050117 is about 1032.2957924251.

Adding to 1100050117 its reverse (7110500011), we get a palindrome (8210550128).

The spelling of 1100050117 in words is "one billion, one hundred million, fifty thousand, one hundred seventeen".