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1100050423 is a prime number
BaseRepresentation
bin100000110010001…
…0110111111110111
32211122221100111021
41001210112333313
54223103103143
6301053522011
736155163043
oct10144267767
92748840437
101100050423
11514a4a18a
122684a3307
13146b9a914
14a6153023
1566895ced
hex41916ff7

1100050423 has 2 divisors, whose sum is σ = 1100050424. Its totient is φ = 1100050422.

The previous prime is 1100050411. The next prime is 1100050453. The reversal of 1100050423 is 3240500011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100050423 is a prime.

It is a super-2 number, since 2×11000504232 = 2420221866284957858, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100050397 and 1100050406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100050453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550025211 + 550025212.

It is an arithmetic number, because the mean of its divisors is an integer number (550025212).

Almost surely, 21100050423 is an apocalyptic number.

1100050423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100050423 is an equidigital number, since it uses as much as digits as its factorization.

1100050423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 1100050423 is about 33167.0080501694. The cubic root of 1100050423 is about 1032.2958881427.

Adding to 1100050423 its reverse (3240500011), we get a palindrome (4340550434).

The spelling of 1100050423 in words is "one billion, one hundred million, fifty thousand, four hundred twenty-three".