Base | Representation |
---|---|
bin | 10000000000100011000… |
… | …100001000110011010111 |
3 | 10220011112212001222022002 |
4 | 100000203010020303113 |
5 | 121011001034234332 |
6 | 2201213503025515 |
7 | 142323333663554 |
oct | 20004304106327 |
9 | 3804485058262 |
10 | 1100099914967 |
11 | 3946057a4649 |
12 | 15925929b29b |
13 | 7c97b6bc161 |
14 | 3b360875a2b |
15 | 1d93963a562 |
hex | 10023108cd7 |
1100099914967 has 2 divisors, whose sum is σ = 1100099914968. Its totient is φ = 1100099914966.
The previous prime is 1100099914939. The next prime is 1100099914987. The reversal of 1100099914967 is 7694199900011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100099914967 - 240 = 588287191 is a prime.
It is a super-2 number, since 2×11000999149672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100099914987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550049957483 + 550049957484.
It is an arithmetic number, because the mean of its divisors is an integer number (550049957484).
Almost surely, 21100099914967 is an apocalyptic number.
1100099914967 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100099914967 is an equidigital number, since it uses as much as digits as its factorization.
1100099914967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1102248, while the sum is 56.
The spelling of 1100099914967 in words is "one trillion, one hundred billion, ninety-nine million, nine hundred fourteen thousand, nine hundred sixty-seven".
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