Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …000010110110100101110011 |
3 | 112102111212001010121111111211 |
4 | 121000312303002312211303 |
5 | 103404400440303101003 |
6 | 1025545521420420551 |
7 | 32112650245511311 |
oct | 3100666302664563 |
9 | 472455033544454 |
10 | 110010001222003 |
11 | 32063a8580a323 |
12 | 104088129a7757 |
13 | 494cb8b2c8bbc |
14 | 1d247263010b1 |
15 | cab92c76296d |
hex | 640db30b6973 |
110010001222003 has 2 divisors, whose sum is σ = 110010001222004. Its totient is φ = 110010001222002.
The previous prime is 110010001221943. The next prime is 110010001222117. The reversal of 110010001222003 is 300222100010011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110010001222003 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010001252003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005000611001 + 55005000611002.
It is an arithmetic number, because the mean of its divisors is an integer number (55005000611002).
Almost surely, 2110010001222003 is an apocalyptic number.
110010001222003 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010001222003 is an equidigital number, since it uses as much as digits as its factorization.
110010001222003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 110010001222003 its reverse (300222100010011), we get a palindrome (410232101232014).
The spelling of 110010001222003 in words is "one hundred ten trillion, ten billion, one million, two hundred twenty-two thousand, three".
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