Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …000010110110100101111100 |
3 | 112102111212001010121111112011 |
4 | 121000312303002312211330 |
5 | 103404400440303101022 |
6 | 1025545521420421004 |
7 | 32112650245511323 |
oct | 3100666302664574 |
9 | 472455033544464 |
10 | 110010001222012 |
11 | 32063a8580a331 |
12 | 104088129a7764 |
13 | 494cb8b2c8bc8 |
14 | 1d247263010ba |
15 | cab92c762977 |
hex | 640db30b697c |
110010001222012 has 6 divisors (see below), whose sum is σ = 192517502138528. Its totient is φ = 55005000611004.
The previous prime is 110010001222003. The next prime is 110010001222117. The reversal of 110010001222012 is 210222100010011.
It is a super-3 number, since 3×1100100012220123 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110010001221983 and 110010001222001.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13751250152748 + ... + 13751250152755.
Almost surely, 2110010001222012 is an apocalyptic number.
It is an amenable number.
110010001222012 is a deficient number, since it is larger than the sum of its proper divisors (82507500916516).
110010001222012 is a wasteful number, since it uses less digits than its factorization.
110010001222012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27502500305507 (or 27502500305505 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 110010001222012 its reverse (210222100010011), we get a palindrome (320232101232023).
The spelling of 110010001222012 in words is "one hundred ten trillion, ten billion, one million, two hundred twenty-two thousand, twelve".
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