Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …101000100100111011011011 |
3 | 112102111212001211012220211211 |
4 | 121000312303220210323123 |
5 | 103404401000321024011 |
6 | 1025545522412403551 |
7 | 32112650425536505 |
oct | 3100666350447333 |
9 | 472455054186754 |
10 | 110010011111131 |
11 | 32063a9035415a |
12 | 104088161765b7 |
13 | 494cb9037c161 |
14 | 1d24727756d75 |
15 | cab92d567b21 |
hex | 640db3a24edb |
110010011111131 has 2 divisors, whose sum is σ = 110010011111132. Its totient is φ = 110010011111130.
The previous prime is 110010011110999. The next prime is 110010011111153. The reversal of 110010011111131 is 131111110010011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110010011111131 - 233 = 110001421176539 is a prime.
It is a super-2 number, since 2×1100100111111312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110010011111171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005555565 + 55005005555566.
It is an arithmetic number, because the mean of its divisors is an integer number (55005005555566).
Almost surely, 2110010011111131 is an apocalyptic number.
110010011111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010011111131 is an equidigital number, since it uses as much as digits as its factorization.
110010011111131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 13.
Adding to 110010011111131 its reverse (131111110010011), we get a palindrome (241121121121142).
The spelling of 110010011111131 in words is "one hundred ten trillion, ten billion, eleven million, one hundred eleven thousand, one hundred thirty-one".
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