11001001307 has 2 divisors, whose sum is σ = 11001001308. Its totient is φ = 11001001306.

The previous prime is 11001001289. The next prime is 11001001321. The reversal of 11001001307 is 70310010011.

It is an a-pointer prime, because the next prime (11001001321) can be obtained adding 11001001307 to its sum of digits (14).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11001001307 - 2⁶ = 11001001243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001001291 and 11001001300.

It is not a weakly prime, because it can be changed into another prime (11001001367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500653 + 5500500654.

It is an arithmetic number, because the mean of its divisors is an integer number (5500500654).

Almost surely, 2^11001001307 is an apocalyptic number.

11001001307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001001307 is an equidigital number, since it uses as much as digits as its factorization.

11001001307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21, while the sum is 14.

Adding to 11001001307 its reverse (70310010011), we get a palindrome (81311011318).

The spelling of 11001001307 in words is "eleven billion, one million, one thousand, three hundred seven".