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1100100497 is a prime number
BaseRepresentation
bin100000110010010…
…0011001110010001
32211200000220011212
41001210203032101
54223111203442
6301054545505
736155462036
oct10144431621
92750026155
101100100497
11514a83871
12268508295
13146bb7652
14a616738d
15668a5a82
hex41923391

1100100497 has 2 divisors, whose sum is σ = 1100100498. Its totient is φ = 1100100496.

The previous prime is 1100100493. The next prime is 1100100499. The reversal of 1100100497 is 7940010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 597264721 + 502835776 = 24439^2 + 22424^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100100497 - 22 = 1100100493 is a prime.

It is a super-2 number, since 2×11001004972 = 2420442206999294018, which contains 22 as substring.

Together with 1100100499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1100100493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050248 + 550050249.

It is an arithmetic number, because the mean of its divisors is an integer number (550050249).

Almost surely, 21100100497 is an apocalyptic number.

It is an amenable number.

1100100497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100100497 is an equidigital number, since it uses as much as digits as its factorization.

1100100497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

The square root of 1100100497 is about 33167.7629182313. The cubic root of 1100100497 is about 1032.3115511823.

The spelling of 1100100497 in words is "one billion, one hundred million, one hundred thousand, four hundred ninety-seven".