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1100101100981 is a prime number
BaseRepresentation
bin10000000000100011001…
…000101010010110110101
310220011112221022020012112
4100000203020222112311
5121011001340212411
62201213544300405
7142323350033411
oct20004310522665
93804487266175
101100101100981
11394606434723
12159259771705
137c97ba15c3c
143b360aa3d41
151d9397c1b8b
hex1002322a5b5

1100101100981 has 2 divisors, whose sum is σ = 1100101100982. Its totient is φ = 1100101100980.

The previous prime is 1100101100947. The next prime is 1100101101017. The reversal of 1100101100981 is 1890011010011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1067388591025 + 32712509956 = 1033145^2 + 180866^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100101100981 is a prime.

It is a super-2 number, since 2×11001011009812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100101102981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050550490 + 550050550491.

It is an arithmetic number, because the mean of its divisors is an integer number (550050550491).

Almost surely, 21100101100981 is an apocalyptic number.

It is an amenable number.

1100101100981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100101100981 is an equidigital number, since it uses as much as digits as its factorization.

1100101100981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 23.

Adding to 1100101100981 its reverse (1890011010011), we get a palindrome (2990112110992).

The spelling of 1100101100981 in words is "one trillion, one hundred billion, one hundred one million, one hundred thousand, nine hundred eighty-one".