110010110132011 has 2 divisors, whose sum is σ = 110010110132012. Its totient is φ = 110010110132010.

The previous prime is 110010110131969. The next prime is 110010110132017. The reversal of 110010110132011 is 110231011010011.

It is a strong prime.

It is an emirp because it is prime and its reverse (110231011010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110010110132011 - 2²¹ = 110010108034859 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110010110131982 and 110010110132000.

It is not a weakly prime, because it can be changed into another prime (110010110132017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005055066005 + 55005055066006.

It is an arithmetic number, because the mean of its divisors is an integer number (55005055066006).

Almost surely, 2^{110010110132011} is an apocalyptic number.

110010110132011 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010110132011 is an equidigital number, since it uses as much as digits as its factorization.

110010110132011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 110010110132011 its reverse (110231011010011), we get a palindrome (220241121142022).

The spelling of 110010110132011 in words is "one hundred ten trillion, ten billion, one hundred ten million, one hundred thirty-two thousand, eleven".