110010110132017 has 2 divisors, whose sum is σ = 110010110132018. Its totient is φ = 110010110132016.

The previous prime is 110010110132011. The next prime is 110010110132063. The reversal of 110010110132017 is 710231011010011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86793892872976 + 23216217259041 = 9316324^2 + 4818321^2 .

It is an emirp because it is prime and its reverse (710231011010011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110010110132017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110010110131985 and 110010110132003.

It is not a weakly prime, because it can be changed into another prime (110010110132011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005055066008 + 55005055066009.

It is an arithmetic number, because the mean of its divisors is an integer number (55005055066009).

Almost surely, 2^{110010110132017} is an apocalyptic number.

It is an amenable number.

110010110132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010110132017 is an equidigital number, since it uses as much as digits as its factorization.

110010110132017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 19.

Adding to 110010110132017 its reverse (710231011010011), we get a palindrome (820241121142028).

The spelling of 110010110132017 in words is "one hundred ten trillion, ten billion, one hundred ten million, one hundred thirty-two thousand, seventeen".