Base | Representation |
---|---|
bin | 10000000000100011001… |
… | …000101111011010101111 |
3 | 10220011112221100021122022 |
4 | 100000203020233122233 |
5 | 121011001341343321 |
6 | 2201213544540355 |
7 | 142323350151014 |
oct | 20004310573257 |
9 | 3804487307568 |
10 | 1100101121711 |
11 | 394606449259 |
12 | 1592597816bb |
13 | 7c97ba224c7 |
14 | 3b360aab70b |
15 | 1d9397c7dab |
hex | 1002322f6af |
1100101121711 has 2 divisors, whose sum is σ = 1100101121712. Its totient is φ = 1100101121710.
The previous prime is 1100101121681. The next prime is 1100101121723. The reversal of 1100101121711 is 1171211010011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100101121711 - 230 = 1099027379887 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1100101121711.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100101121771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050560855 + 550050560856.
It is an arithmetic number, because the mean of its divisors is an integer number (550050560856).
Almost surely, 21100101121711 is an apocalyptic number.
1100101121711 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100101121711 is an equidigital number, since it uses as much as digits as its factorization.
1100101121711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 17.
Adding to 1100101121711 its reverse (1171211010011), we get a palindrome (2271312131722).
The spelling of 1100101121711 in words is "one trillion, one hundred billion, one hundred one million, one hundred twenty-one thousand, seven hundred eleven".
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