110010120133 has 2 divisors, whose sum is σ = 110010120134. Its totient is φ = 110010120132.

The previous prime is 110010120127. The next prime is 110010120179. The reversal of 110010120133 is 331021010011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102862601284 + 7147518849 = 320722^2 + 84543^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010120133 - 2¹³ = 110010111941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010120433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005060066 + 55005060067.

It is an arithmetic number, because the mean of its divisors is an integer number (55005060067).

Almost surely, 2^110010120133 is an apocalyptic number.

It is an amenable number.

110010120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010120133 is an equidigital number, since it uses as much as digits as its factorization.

110010120133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 110010120133 its reverse (331021010011), we get a palindrome (441031130144).

The spelling of 110010120133 in words is "one hundred ten billion, ten million, one hundred twenty thousand, one hundred thirty-three".