Base | Representation |
---|---|
bin | 11001000000110110111110… |
… | …111101011101000001010101 |
3 | 112102111212120001210001001001 |
4 | 121000312332331131001111 |
5 | 103404401342442230031 |
6 | 1025545553321303301 |
7 | 32112655223645521 |
oct | 3100667675350125 |
9 | 472455501701031 |
10 | 110010201133141 |
11 | 32064078641541 |
12 | 10408869934b31 |
13 | 494cbc085190a |
14 | 1d24744a9cd81 |
15 | cab9400a0861 |
hex | 640dbef5d055 |
110010201133141 has 2 divisors, whose sum is σ = 110010201133142. Its totient is φ = 110010201133140.
The previous prime is 110010201133127. The next prime is 110010201133171. The reversal of 110010201133141 is 141331102010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 62454405896100 + 47555795237041 = 7902810^2 + 6896071^2 .
It is a cyclic number.
It is not a de Polignac number, because 110010201133141 - 223 = 110010192744533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010201133111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005100566570 + 55005100566571.
It is an arithmetic number, because the mean of its divisors is an integer number (55005100566571).
Almost surely, 2110010201133141 is an apocalyptic number.
It is an amenable number.
110010201133141 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010201133141 is an equidigital number, since it uses as much as digits as its factorization.
110010201133141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 110010201133141 its reverse (141331102010011), we get a palindrome (251341303143152).
The spelling of 110010201133141 in words is "one hundred ten trillion, ten billion, two hundred one million, one hundred thirty-three thousand, one hundred forty-one".
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