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110010209959957 is a prime number
BaseRepresentation
bin11001000000110110111111…
…011111001000000000010101
3112102111212120200101111011011
4121000312333133020000111
5103404401402222204312
61025545554234412221
732112655361660626
oct3100667737100025
9472455520344134
10110010209959957
113206408262022a
1210408870891071
13494cbc2622498
141d24745d19a4d
15cab940c45da7
hex640dbf7c8015

110010209959957 has 2 divisors, whose sum is σ = 110010209959958. Its totient is φ = 110010209959956.

The previous prime is 110010209959943. The next prime is 110010209959967. The reversal of 110010209959957 is 759959902010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108343242345636 + 1666967614321 = 10408806^2 + 1291111^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010209959957 - 231 = 110008062476309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010209959967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005104979978 + 55005104979979.

It is an arithmetic number, because the mean of its divisors is an integer number (55005104979979).

Almost surely, 2110010209959957 is an apocalyptic number.

It is an amenable number.

110010209959957 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010209959957 is an equidigital number, since it uses as much as digits as its factorization.

110010209959957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2296350, while the sum is 58.

The spelling of 110010209959957 in words is "one hundred ten trillion, ten billion, two hundred nine million, nine hundred fifty-nine thousand, nine hundred fifty-seven".