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110010212120983 is a prime number
BaseRepresentation
bin11001000000110110111111…
…100111010111100110010111
3112102111212120211110021112011
4121000312333213113212113
5103404401403300332413
61025545554353005051
732112655416231166
oct3100667747274627
9472455524407464
10110010212120983
11320640838668a9
1210408871553787
13494cbc2bcacb5
141d2474631d3dd
15cab94102133d
hex640dbf9d7997

110010212120983 has 2 divisors, whose sum is σ = 110010212120984. Its totient is φ = 110010212120982.

The previous prime is 110010212120957. The next prime is 110010212121059. The reversal of 110010212120983 is 389021212010011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110010212120983 - 25 = 110010212120951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010212120183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005106060491 + 55005106060492.

It is an arithmetic number, because the mean of its divisors is an integer number (55005106060492).

Almost surely, 2110010212120983 is an apocalyptic number.

110010212120983 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010212120983 is an equidigital number, since it uses as much as digits as its factorization.

110010212120983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 31.

Adding to 110010212120983 its reverse (389021212010011), we get a palindrome (499031424130994).

The spelling of 110010212120983 in words is "one hundred ten trillion, ten billion, two hundred twelve million, one hundred twenty thousand, nine hundred eighty-three".