Base | Representation |
---|---|
bin | 11001000000110110111111… |
… | …100111010111100110010111 |
3 | 112102111212120211110021112011 |
4 | 121000312333213113212113 |
5 | 103404401403300332413 |
6 | 1025545554353005051 |
7 | 32112655416231166 |
oct | 3100667747274627 |
9 | 472455524407464 |
10 | 110010212120983 |
11 | 320640838668a9 |
12 | 10408871553787 |
13 | 494cbc2bcacb5 |
14 | 1d2474631d3dd |
15 | cab94102133d |
hex | 640dbf9d7997 |
110010212120983 has 2 divisors, whose sum is σ = 110010212120984. Its totient is φ = 110010212120982.
The previous prime is 110010212120957. The next prime is 110010212121059. The reversal of 110010212120983 is 389021212010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110010212120983 - 25 = 110010212120951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010212120183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005106060491 + 55005106060492.
It is an arithmetic number, because the mean of its divisors is an integer number (55005106060492).
Almost surely, 2110010212120983 is an apocalyptic number.
110010212120983 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010212120983 is an equidigital number, since it uses as much as digits as its factorization.
110010212120983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 31.
Adding to 110010212120983 its reverse (389021212010011), we get a palindrome (499031424130994).
The spelling of 110010212120983 in words is "one hundred ten trillion, ten billion, two hundred twelve million, one hundred twenty thousand, nine hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •