Base | Representation |
---|---|
bin | 10000000000100011001… |
… | …110000000111111110000 |
3 | 10220011120000221112101012 |
4 | 100000203032000333300 |
5 | 121011002220120212 |
6 | 2201214034330052 |
7 | 142323365000201 |
oct | 20004316007760 |
9 | 3804500845335 |
10 | 1100102504432 |
11 | 3946072030a8 |
12 | 15925a129928 |
13 | 7c97c0b7999 |
14 | 3b360d4b5a8 |
15 | 1d93999c922 |
hex | 10023380ff0 |
1100102504432 has 10 divisors (see below), whose sum is σ = 2131448602368. Its totient is φ = 550051252208.
The previous prime is 1100102504407. The next prime is 1100102504461. The reversal of 1100102504432 is 2344052010011.
It is a junction number, because it is equal to n+sod(n) for n = 1100102504398 and 1100102504407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34378203248 + ... + 34378203279.
Almost surely, 21100102504432 is an apocalyptic number.
It is an amenable number.
1100102504432 is a deficient number, since it is larger than the sum of its proper divisors (1031346097936).
1100102504432 is an equidigital number, since it uses as much as digits as its factorization.
1100102504432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68756406535 (or 68756406529 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 1100102504432 its reverse (2344052010011), we get a palindrome (3444154514443).
The spelling of 1100102504432 in words is "one trillion, one hundred billion, one hundred two million, five hundred four thousand, four hundred thirty-two".
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