Base | Representation |
---|---|
bin | 1010000000010110000100… |
… | …1100111000100101111111 |
3 | 1102221200121112101101210120 |
4 | 2200011201030320211333 |
5 | 2420220113223400133 |
6 | 35221450421310023 |
7 | 2213541035143632 |
oct | 240054114704577 |
9 | 42850545341716 |
10 | 11001042012543 |
11 | 3561574468400 |
12 | 12980aa865313 |
13 | 61a517280b1b |
14 | 2a064badbc19 |
15 | 141267dd8ab3 |
hex | a016133897f |
11001042012543 has 48 divisors (see below), whose sum is σ = 16218794592000. Its totient is φ = 6627689622400.
The previous prime is 11001042012517. The next prime is 11001042012551. The reversal of 11001042012543 is 34521024010011.
It is not a de Polignac number, because 11001042012543 - 214 = 11001041996159 is a prime.
It is a super-2 number, since 2×110010420125432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001042012503) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 42610558 + ... + 42867956.
It is an arithmetic number, because the mean of its divisors is an integer number (337891554000).
Almost surely, 211001042012543 is an apocalyptic number.
11001042012543 is a deficient number, since it is larger than the sum of its proper divisors (5217752579457).
11001042012543 is a wasteful number, since it uses less digits than its factorization.
11001042012543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258124 (or 258113 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 11001042012543 its reverse (34521024010011), we get a palindrome (45522066022554).
The spelling of 11001042012543 in words is "eleven trillion, one billion, forty-two million, twelve thousand, five hundred forty-three".
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