Base | Representation |
---|---|
bin | 1010000000010110000111… |
… | …1110000101101010100001 |
3 | 1102221200122102122201100021 |
4 | 2200011201332011222201 |
5 | 2420220130024124022 |
6 | 35221452001553441 |
7 | 2213541252605104 |
oct | 240054176055241 |
9 | 42850572581307 |
10 | 11001054911137 |
11 | 35615807782a5 |
12 | 12980b3045881 |
13 | 61a519b48b25 |
14 | 2a064d6d873b |
15 | 1412690d57c7 |
hex | a0161f85aa1 |
11001054911137 has 2 divisors, whose sum is σ = 11001054911138. Its totient is φ = 11001054911136.
The previous prime is 11001054911131. The next prime is 11001054911149. The reversal of 11001054911137 is 73111945010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10240742413456 + 760312497681 = 3200116^2 + 871959^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001054911137 - 231 = 10998907427489 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001054911131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500527455568 + 5500527455569.
It is an arithmetic number, because the mean of its divisors is an integer number (5500527455569).
Almost surely, 211001054911137 is an apocalyptic number.
It is an amenable number.
11001054911137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001054911137 is an equidigital number, since it uses as much as digits as its factorization.
11001054911137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 34.
Adding to 11001054911137 its reverse (73111945010011), we get a palindrome (84112999921148).
The spelling of 11001054911137 in words is "eleven trillion, one billion, fifty-four million, nine hundred eleven thousand, one hundred thirty-seven".
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