11001100001053 has 2 divisors, whose sum is σ = 11001100001054. Its totient is φ = 11001100001052.

The previous prime is 11001100001033. The next prime is 11001100001069. The reversal of 11001100001053 is 35010000110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10995842736004 + 5257265049 = 3315998^2 + 72507^2 .

It is an emirp because it is prime and its reverse (35010000110011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001100001053 is a prime.

It is a super-2 number, since 2×11001100001053² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001100001033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550000526 + 5500550000527.

It is an arithmetic number, because the mean of its divisors is an integer number (5500550000527).

Almost surely, 2^{11001100001053} is an apocalyptic number.

It is an amenable number.

11001100001053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001100001053 is an equidigital number, since it uses as much as digits as its factorization.

11001100001053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 11001100001053 its reverse (35010000110011), we get a palindrome (46011100111064).

The spelling of 11001100001053 in words is "eleven trillion, one billion, one hundred million, one thousand, fifty-three".