Base | Representation |
---|---|
bin | 11001000000110111101110… |
… | …100100111011100110001111 |
3 | 112102111221121202000020122111 |
4 | 121000313232210323212033 |
5 | 103404410012000324101 |
6 | 1025550204500124451 |
7 | 32113014064210111 |
oct | 3100675644734617 |
9 | 472457552006574 |
10 | 110011000011151 |
11 | 320644485863a8 |
12 | 10408a51396727 |
13 | 494ccba200bb5 |
14 | 1d247bcc153b1 |
15 | cab98a2a5251 |
hex | 640dee93b98f |
110011000011151 has 2 divisors, whose sum is σ = 110011000011152. Its totient is φ = 110011000011150.
The previous prime is 110011000011137. The next prime is 110011000011167. The reversal of 110011000011151 is 151110000110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110011000011151 - 217 = 110010999880079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011000015151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005500005575 + 55005500005576.
It is an arithmetic number, because the mean of its divisors is an integer number (55005500005576).
Almost surely, 2110011000011151 is an apocalyptic number.
110011000011151 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011000011151 is an equidigital number, since it uses as much as digits as its factorization.
110011000011151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 13.
Adding to 110011000011151 its reverse (151110000110011), we get a palindrome (261121000121162).
The spelling of 110011000011151 in words is "one hundred ten trillion, eleven billion, eleven thousand, one hundred fifty-one".
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