Base | Representation |
---|---|
bin | 11001000000110111101110… |
… | …101001000101101011001011 |
3 | 112102111221121211001121122101 |
4 | 121000313232221011223023 |
5 | 103404410012240213003 |
6 | 1025550204535334231 |
7 | 32113014106366402 |
oct | 3100675651055313 |
9 | 472457554047571 |
10 | 110011001101003 |
11 | 32064449160202 |
12 | 10408a51821377 |
13 | 494ccba4c2c92 |
14 | 1d247bd01a639 |
15 | cab98a41d11d |
hex | 640deea45acb |
110011001101003 has 2 divisors, whose sum is σ = 110011001101004. Its totient is φ = 110011001101002.
The previous prime is 110011001100929. The next prime is 110011001101007. The reversal of 110011001101003 is 300101100110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110011001101003 - 217 = 110011000969931 is a prime.
It is not a weakly prime, because it can be changed into another prime (110011001101007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005500550501 + 55005500550502.
It is an arithmetic number, because the mean of its divisors is an integer number (55005500550502).
Almost surely, 2110011001101003 is an apocalyptic number.
110011001101003 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011001101003 is an equidigital number, since it uses as much as digits as its factorization.
110011001101003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 10.
Adding to 110011001101003 its reverse (300101100110011), we get a palindrome (410112101211014).
The spelling of 110011001101003 in words is "one hundred ten trillion, eleven billion, one million, one hundred one thousand, three".
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