Base | Representation |
---|---|
bin | 1010000000010110010010… |
… | …1101111010000100000011 |
3 | 1102221200202122101022200212 |
4 | 2200011210231322010003 |
5 | 2420220223324012323 |
6 | 35221500325504335 |
7 | 2213542352425553 |
oct | 240054455720403 |
9 | 42850678338625 |
10 | 11001101000963 |
11 | 35615a4798267 |
12 | 12981065720ab |
13 | 61a526565508 |
14 | 2a0655895163 |
15 | 14126d18bb78 |
hex | a0164b7a103 |
11001101000963 has 2 divisors, whose sum is σ = 11001101000964. Its totient is φ = 11001101000962.
The previous prime is 11001101000951. The next prime is 11001101000983. The reversal of 11001101000963 is 36900010110011.
It is a weak prime.
It is an emirp because it is prime and its reverse (36900010110011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11001101000963 - 222 = 11001096806659 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001101000983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550500481 + 5500550500482.
It is an arithmetic number, because the mean of its divisors is an integer number (5500550500482).
Almost surely, 211001101000963 is an apocalyptic number.
11001101000963 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001101000963 is an equidigital number, since it uses as much as digits as its factorization.
11001101000963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 23.
Adding to 11001101000963 its reverse (36900010110011), we get a palindrome (47901111110974).
The spelling of 11001101000963 in words is "eleven trillion, one billion, one hundred one million, nine hundred sixty-three", and thus it is an aban number.
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