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11001101000963 is a prime number
BaseRepresentation
bin1010000000010110010010…
…1101111010000100000011
31102221200202122101022200212
42200011210231322010003
52420220223324012323
635221500325504335
72213542352425553
oct240054455720403
942850678338625
1011001101000963
1135615a4798267
1212981065720ab
1361a526565508
142a0655895163
1514126d18bb78
hexa0164b7a103

11001101000963 has 2 divisors, whose sum is σ = 11001101000964. Its totient is φ = 11001101000962.

The previous prime is 11001101000951. The next prime is 11001101000983. The reversal of 11001101000963 is 36900010110011.

It is a weak prime.

It is an emirp because it is prime and its reverse (36900010110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001101000963 - 222 = 11001096806659 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001101000983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550500481 + 5500550500482.

It is an arithmetic number, because the mean of its divisors is an integer number (5500550500482).

Almost surely, 211001101000963 is an apocalyptic number.

11001101000963 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001101000963 is an equidigital number, since it uses as much as digits as its factorization.

11001101000963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 23.

Adding to 11001101000963 its reverse (36900010110011), we get a palindrome (47901111110974).

The spelling of 11001101000963 in words is "eleven trillion, one billion, one hundred one million, nine hundred sixty-three", and thus it is an aban number.