11001101000983 has 2 divisors, whose sum is σ = 11001101000984. Its totient is φ = 11001101000982.

The previous prime is 11001101000963. The next prime is 11001101000993. The reversal of 11001101000983 is 38900010110011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11001101000983 - 2⁵ = 11001101000951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001101000963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550500491 + 5500550500492.

It is an arithmetic number, because the mean of its divisors is an integer number (5500550500492).

Almost surely, 2^{11001101000983} is an apocalyptic number.

11001101000983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001101000983 is an equidigital number, since it uses as much as digits as its factorization.

11001101000983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 25.

Adding to 11001101000983 its reverse (38900010110011), we get a palindrome (49901111110994).

The spelling of 11001101000983 in words is "eleven trillion, one billion, one hundred one million, nine hundred eighty-three", and thus it is an aban number.