Base | Representation |
---|---|
bin | 11001000000110111101111… |
… | …001111001111000111010101 |
3 | 112102111221122111212200020212 |
4 | 121000313233033033013111 |
5 | 103404410022320214031 |
6 | 1025550205533535205 |
7 | 32113014260366333 |
oct | 3100675717170725 |
9 | 472457574780225 |
10 | 110011011101141 |
11 | 32064453870487 |
12 | 10408a55044505 |
13 | 494ccbc5b4917 |
14 | 1d247c04a0b53 |
15 | cab98b24612b |
hex | 640def3cf1d5 |
110011011101141 has 2 divisors, whose sum is σ = 110011011101142. Its totient is φ = 110011011101140.
The previous prime is 110011011101099. The next prime is 110011011101171. The reversal of 110011011101141 is 141101110110011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78808408308100 + 31202602793041 = 8877410^2 + 5585929^2 .
It is a cyclic number.
It is not a de Polignac number, because 110011011101141 - 214 = 110011011084757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011011101171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005505550570 + 55005505550571.
It is an arithmetic number, because the mean of its divisors is an integer number (55005505550571).
Almost surely, 2110011011101141 is an apocalyptic number.
It is an amenable number.
110011011101141 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011011101141 is an equidigital number, since it uses as much as digits as its factorization.
110011011101141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 14.
Adding to 110011011101141 its reverse (141101110110011), we get a palindrome (251112121211152).
The spelling of 110011011101141 in words is "one hundred ten trillion, eleven billion, eleven million, one hundred one thousand, one hundred forty-one".
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