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110011012099997 is a prime number
BaseRepresentation
bin11001000000110111101111…
…010011000010111110011101
3112102111221122120202102102112
4121000313233103002332131
5103404410023044144442
61025550210011203405
732113014302026421
oct3100675723027635
9472457576672375
10110011012099997
1132064454392988
1210408a55446565
13494ccbc874468
141d247c0680b81
15cab98b392082
hex640def4c2f9d

110011012099997 has 2 divisors, whose sum is σ = 110011012099998. Its totient is φ = 110011012099996.

The previous prime is 110011012099973. The next prime is 110011012100039. The reversal of 110011012099997 is 799990210110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71833269653401 + 38177742446596 = 8475451^2 + 6178814^2 .

It is a cyclic number.

It is not a de Polignac number, because 110011012099997 - 238 = 109736134193053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011012099907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005506049998 + 55005506049999.

It is an arithmetic number, because the mean of its divisors is an integer number (55005506049999).

Almost surely, 2110011012099997 is an apocalyptic number.

It is an amenable number.

110011012099997 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011012099997 is an equidigital number, since it uses as much as digits as its factorization.

110011012099997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 91854, while the sum is 50.

The spelling of 110011012099997 in words is "one hundred ten trillion, eleven billion, twelve million, ninety-nine thousand, nine hundred ninety-seven".