Base | Representation |
---|---|
bin | 11001000000110111101111… |
… | …010011000010111110011101 |
3 | 112102111221122120202102102112 |
4 | 121000313233103002332131 |
5 | 103404410023044144442 |
6 | 1025550210011203405 |
7 | 32113014302026421 |
oct | 3100675723027635 |
9 | 472457576672375 |
10 | 110011012099997 |
11 | 32064454392988 |
12 | 10408a55446565 |
13 | 494ccbc874468 |
14 | 1d247c0680b81 |
15 | cab98b392082 |
hex | 640def4c2f9d |
110011012099997 has 2 divisors, whose sum is σ = 110011012099998. Its totient is φ = 110011012099996.
The previous prime is 110011012099973. The next prime is 110011012100039. The reversal of 110011012099997 is 799990210110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 71833269653401 + 38177742446596 = 8475451^2 + 6178814^2 .
It is a cyclic number.
It is not a de Polignac number, because 110011012099997 - 238 = 109736134193053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011012099907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005506049998 + 55005506049999.
It is an arithmetic number, because the mean of its divisors is an integer number (55005506049999).
Almost surely, 2110011012099997 is an apocalyptic number.
It is an amenable number.
110011012099997 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011012099997 is an equidigital number, since it uses as much as digits as its factorization.
110011012099997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91854, while the sum is 50.
The spelling of 110011012099997 in words is "one hundred ten trillion, eleven billion, twelve million, ninety-nine thousand, nine hundred ninety-seven".
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