11001101220127 has 2 divisors, whose sum is σ = 11001101220128. Its totient is φ = 11001101220126.

The previous prime is 11001101220113. The next prime is 11001101220149. The reversal of 11001101220127 is 72102210110011.

11001101220127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (72102210110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001101220127 - 2³¹ = 10998953736479 is a prime.

It is a super-2 number, since 2×11001101220127² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001101220167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550610063 + 5500550610064.

It is an arithmetic number, because the mean of its divisors is an integer number (5500550610064).

Almost surely, 2^{11001101220127} is an apocalyptic number.

11001101220127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001101220127 is an equidigital number, since it uses as much as digits as its factorization.

11001101220127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 11001101220127 its reverse (72102210110011), we get a palindrome (83103311330138).

The spelling of 11001101220127 in words is "eleven trillion, one billion, one hundred one million, two hundred twenty thousand, one hundred twenty-seven".