1100110133321 has 2 divisors, whose sum is σ = 1100110133322. Its totient is φ = 1100110133320.

The previous prime is 1100110133273. The next prime is 1100110133323. The reversal of 1100110133321 is 1233310110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1095130855225 + 4979278096 = 1046485^2 + 70564^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100110133321 - 2²² = 1100105939017 is a prime.

Together with 1100110133323, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100110133321.

It is not a weakly prime, because it can be changed into another prime (1100110133323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055066660 + 550055066661.

It is an arithmetic number, because the mean of its divisors is an integer number (550055066661).

Almost surely, 2^{1100110133321} is an apocalyptic number.

It is an amenable number.

1100110133321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100110133321 is an equidigital number, since it uses as much as digits as its factorization.

1100110133321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100110133321 its reverse (1233310110011), we get a palindrome (2333420243332).

The spelling of 1100110133321 in words is "one trillion, one hundred billion, one hundred ten million, one hundred thirty-three thousand, three hundred twenty-one".