Base | Representation |
---|---|
bin | 100000110010010… |
… | …0101110010010001 |
3 | 2211200001102120121 |
4 | 1001210211302101 |
5 | 4223112022433 |
6 | 301055110241 |
7 | 36155534452 |
oct | 10144456221 |
9 | 2750042517 |
10 | 1100110993 |
11 | 514a90743 |
12 | 268512381 |
13 | 146bbc367 |
14 | a616b129 |
15 | 668a8c2d |
hex | 41925c91 |
1100110993 has 2 divisors, whose sum is σ = 1100110994. Its totient is φ = 1100110992.
The previous prime is 1100110951. The next prime is 1100111003. The reversal of 1100110993 is 3990110011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1076364864 + 23746129 = 32808^2 + 4873^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100110993 - 217 = 1099979921 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100110903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055496 + 550055497.
It is an arithmetic number, because the mean of its divisors is an integer number (550055497).
Almost surely, 21100110993 is an apocalyptic number.
It is an amenable number.
1100110993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100110993 is an equidigital number, since it uses as much as digits as its factorization.
1100110993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 25.
The square root of 1100110993 is about 33167.9211437799. The cubic root of 1100110993 is about 1032.3148342483.
The spelling of 1100110993 in words is "one billion, one hundred million, one hundred ten thousand, nine hundred ninety-three".
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