Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …0000100111110000100111 |
3 | 1102221200210021111122122102 |
4 | 2200011211100213300213 |
5 | 2420220233141213111 |
6 | 35221501252522315 |
7 | 2213542522656431 |
oct | 240054520476047 |
9 | 42850707448572 |
10 | 11001110101031 |
11 | 35615a9943286 |
12 | 129810962039b |
13 | 61a52840057b |
14 | 2a0656b83651 |
15 | 14126dd8813b |
hex | a0165427c27 |
11001110101031 has 2 divisors, whose sum is σ = 11001110101032. Its totient is φ = 11001110101030.
The previous prime is 11001110100971. The next prime is 11001110101049. The reversal of 11001110101031 is 13010101110011.
It is a strong prime.
It is an emirp because it is prime and its reverse (13010101110011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001110101031 is a prime.
It is a super-2 number, since 2×110011101010312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001110401031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555050515 + 5500555050516.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555050516).
Almost surely, 211001110101031 is an apocalyptic number.
11001110101031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001110101031 is an equidigital number, since it uses as much as digits as its factorization.
11001110101031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 11001110101031 its reverse (13010101110011), we get a palindrome (24011211211042).
The spelling of 11001110101031 in words is "eleven trillion, one billion, one hundred ten million, one hundred one thousand, thirty-one".
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