Base | Representation |
---|---|
bin | 11001000000110111110101… |
… | …000110100011000011100011 |
3 | 112102111221220101000012000212 |
4 | 121000313311012203003203 |
5 | 103404410223012034234 |
6 | 1025550223410404335 |
7 | 32113016563556132 |
oct | 3100676506430343 |
9 | 472457811005025 |
10 | 110011109486819 |
11 | 320644a435a062 |
12 | 10408a81b906ab |
13 | 4950006ab16b8 |
14 | 1d247cd591919 |
15 | cab994bcc5ce |
hex | 640df51a30e3 |
110011109486819 has 2 divisors, whose sum is σ = 110011109486820. Its totient is φ = 110011109486818.
The previous prime is 110011109486771. The next prime is 110011109486821. The reversal of 110011109486819 is 918684901110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110011109486819 - 28 = 110011109486563 is a prime.
It is a super-2 number, since 2×1100111094868192 (a number of 29 digits) contains 22 as substring.
Together with 110011109486821, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (110011103486819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005554743409 + 55005554743410.
It is an arithmetic number, because the mean of its divisors is an integer number (55005554743410).
Almost surely, 2110011109486819 is an apocalyptic number.
110011109486819 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011109486819 is an equidigital number, since it uses as much as digits as its factorization.
110011109486819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 50.
The spelling of 110011109486819 in words is "one hundred ten trillion, eleven billion, one hundred nine million, four hundred eighty-six thousand, eight hundred nineteen".
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