110011110011083 has 2 divisors, whose sum is σ = 110011110011084. Its totient is φ = 110011110011082.

The previous prime is 110011110011071. The next prime is 110011110011093. The reversal of 110011110011083 is 380110011110011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110011110011083 - 2⁴¹ = 107812086755531 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110011110011083.

It is not a weakly prime, because it can be changed into another prime (110011110011093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005555005541 + 55005555005542.

It is an arithmetic number, because the mean of its divisors is an integer number (55005555005542).

Almost surely, 2^{110011110011083} is an apocalyptic number.

110011110011083 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011110011083 is an equidigital number, since it uses as much as digits as its factorization.

110011110011083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 19.

Adding to 110011110011083 its reverse (380110011110011), we get a palindrome (490121121121094).

The spelling of 110011110011083 in words is "one hundred ten trillion, eleven billion, one hundred ten million, eleven thousand, eighty-three".