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110011121201257 is a prime number
BaseRepresentation
bin11001000000110111110101…
…110011001111000001101001
3112102111221221012001100012221
4121000313311303033001221
5103404410234011420012
61025550224505434041
732113020065256043
oct3100676563170151
9472457835040187
10110011121201257
11320644aaa30311
1210408a85a9b921
134950009353713
141d247d0d60a93
15cab995c43507
hex640df5ccf069

110011121201257 has 2 divisors, whose sum is σ = 110011121201258. Its totient is φ = 110011121201256.

The previous prime is 110011121201207. The next prime is 110011121201291. The reversal of 110011121201257 is 752102121110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87002703970576 + 23008417230681 = 9327524^2 + 4796709^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110011121201257 is a prime.

It is not a weakly prime, because it can be changed into another prime (110011121201207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005560600628 + 55005560600629.

It is an arithmetic number, because the mean of its divisors is an integer number (55005560600629).

Almost surely, 2110011121201257 is an apocalyptic number.

It is an amenable number.

110011121201257 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011121201257 is an equidigital number, since it uses as much as digits as its factorization.

110011121201257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 25.

Adding to 110011121201257 its reverse (752102121110011), we get a palindrome (862113242311268).

The spelling of 110011121201257 in words is "one hundred ten trillion, eleven billion, one hundred twenty-one million, two hundred one thousand, two hundred fifty-seven".