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1100111221023 = 35364303107599
BaseRepresentation
bin10000000000100011101…
…111010001000100011111
310220011120122100101021220
4100000203233101010133
5121011011433033043
62201214545224423
7142323532043043
oct20004357210437
93804518311256
101100111221023
11394611116aa1
12159261032113
137c980b4a329
143b36217a023
151d93a620483
hex10023bd111f

1100111221023 has 16 divisors (see below), whose sum is σ = 1494527846400. Its totient is φ = 719551725984.

The previous prime is 1100111220991. The next prime is 1100111221051. The reversal of 1100111221023 is 3201221110011.

It is not a de Polignac number, because 1100111221023 - 25 = 1100111220991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100111220993 and 1100111221011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100111221823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10170378 + ... + 10277976.

It is an arithmetic number, because the mean of its divisors is an integer number (93407990400).

Almost surely, 21100111221023 is an apocalyptic number.

1100111221023 is a deficient number, since it is larger than the sum of its proper divisors (394416625377).

1100111221023 is a wasteful number, since it uses less digits than its factorization.

1100111221023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171958.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1100111221023 its reverse (3201221110011), we get a palindrome (4301332331034).

The spelling of 1100111221023 in words is "one trillion, one hundred billion, one hundred eleven million, two hundred twenty-one thousand, twenty-three".

Divisors: 1 3 53 159 64303 107599 192909 322797 3408059 5702747 10224177 17108241 6918938497 20756815491 366703740341 1100111221023