Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …010101000001011111111 |
3 | 10220011120201000010221222 |
4 | 100000203302220023333 |
5 | 121011012144232033 |
6 | 2201215020143555 |
7 | 142323542402645 |
oct | 20004362501377 |
9 | 3804521003858 |
10 | 1100112102143 |
11 | 394611668a9a |
12 | 159261397bbb |
13 | 7c9810983c2 |
14 | 3b362329195 |
15 | 1d93a746598 |
hex | 10023ca82ff |
1100112102143 has 2 divisors, whose sum is σ = 1100112102144. Its totient is φ = 1100112102142.
The previous prime is 1100112102091. The next prime is 1100112102161. The reversal of 1100112102143 is 3412012110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100112102143 - 28 = 1100112101887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100112102443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056051071 + 550056051072.
It is an arithmetic number, because the mean of its divisors is an integer number (550056051072).
Almost surely, 21100112102143 is an apocalyptic number.
1100112102143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100112102143 is an equidigital number, since it uses as much as digits as its factorization.
1100112102143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1100112102143 its reverse (3412012110011), we get a palindrome (4512124212154).
The spelling of 1100112102143 in words is "one trillion, one hundred billion, one hundred twelve million, one hundred two thousand, one hundred forty-three".
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