Base | Representation |
---|---|
bin | 10100011111011011… |
… | …11100101000010111 |
3 | 1001101200112212101011 |
4 | 22033231330220113 |
5 | 140012241340203 |
6 | 5015344113051 |
7 | 536421662644 |
oct | 121755745027 |
9 | 31350485334 |
10 | 11001121303 |
11 | 4735934297 |
12 | 2170305787 |
13 | 106422ab43 |
14 | 7650c2dcb |
15 | 445c1176d |
hex | 28fb7ca17 |
11001121303 has 2 divisors, whose sum is σ = 11001121304. Its totient is φ = 11001121302.
The previous prime is 11001121291. The next prime is 11001121337. The reversal of 11001121303 is 30312110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001121303 - 213 = 11001113111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001121003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500560651 + 5500560652.
It is an arithmetic number, because the mean of its divisors is an integer number (5500560652).
Almost surely, 211001121303 is an apocalyptic number.
11001121303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001121303 is an equidigital number, since it uses as much as digits as its factorization.
11001121303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11001121303 its reverse (30312110011), we get a palindrome (41313231314).
The spelling of 11001121303 in words is "eleven billion, one million, one hundred twenty-one thousand, three hundred three".
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