Base | Representation |
---|---|
bin | 110011001110100101… |
… | …1100000110110000111 |
3 | 101111221212112012000201 |
4 | 1212131023200312013 |
5 | 3300300333122211 |
6 | 122312150151331 |
7 | 10643115653554 |
oct | 1463513406607 |
9 | 344855465021 |
10 | 110011223431 |
11 | 4272351647a |
12 | 193a2652547 |
13 | a4b29295a5 |
14 | 54788a5a2b |
15 | 2cdd0b30c1 |
hex | 199d2e0d87 |
110011223431 has 2 divisors, whose sum is σ = 110011223432. Its totient is φ = 110011223430.
The previous prime is 110011223417. The next prime is 110011223459. The reversal of 110011223431 is 134322110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110011223431 - 27 = 110011223303 is a prime.
It is a super-2 number, since 2×1100112234312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110011223399 and 110011223408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011223401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005611715 + 55005611716.
It is an arithmetic number, because the mean of its divisors is an integer number (55005611716).
Almost surely, 2110011223431 is an apocalyptic number.
110011223431 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011223431 is an equidigital number, since it uses as much as digits as its factorization.
110011223431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 110011223431 its reverse (134322110011), we get a palindrome (244333333442).
The spelling of 110011223431 in words is "one hundred ten billion, eleven million, two hundred twenty-three thousand, four hundred thirty-one".
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