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11001130350097 is a prime number
BaseRepresentation
bin1010000000010110011001…
…1101110111011000010001
31102221200211200121102010211
42200011212131313120101
52420220303332200342
635221503254524121
72213543160043546
oct240054635673021
942850750542124
1011001130350097
11356160a313748
121298114366641
1361a52c670174
142a0659734bcd
15141270a37c17
hexa0166777611

11001130350097 has 2 divisors, whose sum is σ = 11001130350098. Its totient is φ = 11001130350096.

The previous prime is 11001130350079. The next prime is 11001130350131. The reversal of 11001130350097 is 79005303110011.

Together with previous prime (11001130350079) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6996665104641 + 4004465245456 = 2645121^2 + 2001116^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001130350097 - 219 = 11001129825809 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001130350017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500565175048 + 5500565175049.

It is an arithmetic number, because the mean of its divisors is an integer number (5500565175049).

Almost surely, 211001130350097 is an apocalyptic number.

It is an amenable number.

11001130350097 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001130350097 is an equidigital number, since it uses as much as digits as its factorization.

11001130350097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2835, while the sum is 31.

The spelling of 11001130350097 in words is "eleven trillion, one billion, one hundred thirty million, three hundred fifty thousand, ninety-seven".