Base | Representation |
---|---|
bin | 1010000000010110011001… |
… | …1101110111011000010001 |
3 | 1102221200211200121102010211 |
4 | 2200011212131313120101 |
5 | 2420220303332200342 |
6 | 35221503254524121 |
7 | 2213543160043546 |
oct | 240054635673021 |
9 | 42850750542124 |
10 | 11001130350097 |
11 | 356160a313748 |
12 | 1298114366641 |
13 | 61a52c670174 |
14 | 2a0659734bcd |
15 | 141270a37c17 |
hex | a0166777611 |
11001130350097 has 2 divisors, whose sum is σ = 11001130350098. Its totient is φ = 11001130350096.
The previous prime is 11001130350079. The next prime is 11001130350131. The reversal of 11001130350097 is 79005303110011.
Together with previous prime (11001130350079) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6996665104641 + 4004465245456 = 2645121^2 + 2001116^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001130350097 - 219 = 11001129825809 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001130350017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500565175048 + 5500565175049.
It is an arithmetic number, because the mean of its divisors is an integer number (5500565175049).
Almost surely, 211001130350097 is an apocalyptic number.
It is an amenable number.
11001130350097 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001130350097 is an equidigital number, since it uses as much as digits as its factorization.
11001130350097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835, while the sum is 31.
The spelling of 11001130350097 in words is "eleven trillion, one billion, one hundred thirty million, three hundred fifty thousand, ninety-seven".
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