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11001130350131 is a prime number
BaseRepresentation
bin1010000000010110011001…
…1101110111011000110011
31102221200211200121102012002
42200011212131313120303
52420220303332201011
635221503254524215
72213543160043625
oct240054635673063
942850750542162
1011001130350131
11356160a313779
12129811436666b
1361a52c67019c
142a0659734c15
15141270a37c3b
hexa0166777633

11001130350131 has 2 divisors, whose sum is σ = 11001130350132. Its totient is φ = 11001130350130.

The previous prime is 11001130350097. The next prime is 11001130350149. The reversal of 11001130350131 is 13105303110011.

11001130350131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11001130350131 is a prime.

It is a super-2 number, since 2×110011303501312 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (11001130350181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500565175065 + 5500565175066.

It is an arithmetic number, because the mean of its divisors is an integer number (5500565175066).

Almost surely, 211001130350131 is an apocalyptic number.

11001130350131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001130350131 is an equidigital number, since it uses as much as digits as its factorization.

11001130350131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 20.

Adding to 11001130350131 its reverse (13105303110011), we get a palindrome (24106433460142).

The spelling of 11001130350131 in words is "eleven trillion, one billion, one hundred thirty million, three hundred fifty thousand, one hundred thirty-one".