Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …110011110110010001001 |
3 | 10220011120202220110111112 |
4 | 100000203312132302021 |
5 | 121011012424042301 |
6 | 2201215053540105 |
7 | 142323554110505 |
oct | 20004366366211 |
9 | 3804522813445 |
10 | 1100113112201 |
11 | 394612198954 |
12 | 1592617a4635 |
13 | 7c98136007c |
14 | 3b36250d305 |
15 | 1d93a8959bb |
hex | 10023d9ec89 |
1100113112201 has 2 divisors, whose sum is σ = 1100113112202. Its totient is φ = 1100113112200.
The previous prime is 1100113112183. The next prime is 1100113112213. The reversal of 1100113112201 is 1022113110011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1030933591801 + 69179520400 = 1015349^2 + 263020^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100113112201 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100113112291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056556100 + 550056556101.
It is an arithmetic number, because the mean of its divisors is an integer number (550056556101).
Almost surely, 21100113112201 is an apocalyptic number.
It is an amenable number.
1100113112201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100113112201 is an equidigital number, since it uses as much as digits as its factorization.
1100113112201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 1100113112201 its reverse (1022113110011), we get a palindrome (2122226222212).
The spelling of 1100113112201 in words is "one trillion, one hundred billion, one hundred thirteen million, one hundred twelve thousand, two hundred one".
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