Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …110011110110010010101 |
3 | 10220011120202220110111222 |
4 | 100000203312132302111 |
5 | 121011012424042323 |
6 | 2201215053540125 |
7 | 142323554110523 |
oct | 20004366366225 |
9 | 3804522813458 |
10 | 1100113112213 |
11 | 394612198965 |
12 | 1592617a4645 |
13 | 7c98136008b |
14 | 3b36250d313 |
15 | 1d93a8959c8 |
hex | 10023d9ec95 |
1100113112213 has 2 divisors, whose sum is σ = 1100113112214. Its totient is φ = 1100113112212.
The previous prime is 1100113112201. The next prime is 1100113112257. The reversal of 1100113112213 is 3122113110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 554284717009 + 545828395204 = 744503^2 + 738802^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100113112213 - 212 = 1100113108117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100113112191 and 1100113112200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100113112513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056556106 + 550056556107.
It is an arithmetic number, because the mean of its divisors is an integer number (550056556107).
Almost surely, 21100113112213 is an apocalyptic number.
It is an amenable number.
1100113112213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100113112213 is an equidigital number, since it uses as much as digits as its factorization.
1100113112213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1100113112213 its reverse (3122113110011), we get a palindrome (4222226222224).
The spelling of 1100113112213 in words is "one trillion, one hundred billion, one hundred thirteen million, one hundred twelve thousand, two hundred thirteen".
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