Base | Representation |
---|---|
bin | 1010000000010110011110… |
… | …1000110100111101010111 |
3 | 1102221200220001120210002102 |
4 | 2200011213220310331113 |
5 | 2420220323400012413 |
6 | 35221505240032315 |
7 | 2213543516060012 |
oct | 240054750647527 |
9 | 42850801523072 |
10 | 11001150000983 |
11 | 356161a41574a |
12 | 129811aa6269b |
13 | 61a5337606cc |
14 | 2a065c1ac379 |
15 | 14127261a458 |
hex | a0167a34f57 |
11001150000983 has 2 divisors, whose sum is σ = 11001150000984. Its totient is φ = 11001150000982.
The previous prime is 11001150000941. The next prime is 11001150001081. The reversal of 11001150000983 is 38900005110011.
11001150000983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001150000983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001150000923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500575000491 + 5500575000492.
It is an arithmetic number, because the mean of its divisors is an integer number (5500575000492).
Almost surely, 211001150000983 is an apocalyptic number.
11001150000983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001150000983 is an equidigital number, since it uses as much as digits as its factorization.
11001150000983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 29.
Adding to 11001150000983 its reverse (38900005110011), we get a palindrome (49901155110994).
The spelling of 11001150000983 in words is "eleven trillion, one billion, one hundred fifty million, nine hundred eighty-three", and thus it is an aban number.
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