110012000020133 has 2 divisors, whose sum is σ = 110012000020134. Its totient is φ = 110012000020132.

The previous prime is 110012000020103. The next prime is 110012000020141. The reversal of 110012000020133 is 331020000210011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64018673361889 + 45993326658244 = 8001167^2 + 6781838^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110012000020133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110012000020103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006000010066 + 55006000010067.

It is an arithmetic number, because the mean of its divisors is an integer number (55006000010067).

Almost surely, 2^{110012000020133} is an apocalyptic number.

It is an amenable number.

110012000020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012000020133 is an equidigital number, since it uses as much as digits as its factorization.

110012000020133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 110012000020133 its reverse (331020000210011), we get a palindrome (441032000230144).

The spelling of 110012000020133 in words is "one hundred ten trillion, twelve billion, twenty thousand, one hundred thirty-three".