Base | Representation |
---|---|
bin | 1010000000010110101010… |
… | …0111100110001101111011 |
3 | 1102221201000112200111201012 |
4 | 2200011222213212031323 |
5 | 2420220424200310412 |
6 | 35221514223544135 |
7 | 2213544664123136 |
oct | 240055247461573 |
9 | 42851015614635 |
10 | 11001200010107 |
11 | 35616456722aa |
12 | 129813375b04b |
13 | 61a540c1ccc8 |
14 | 2a0664aa921d |
15 | 141276be7c22 |
hex | a016a9e637b |
11001200010107 has 2 divisors, whose sum is σ = 11001200010108. Its totient is φ = 11001200010106.
The previous prime is 11001200009959. The next prime is 11001200010113. The reversal of 11001200010107 is 70101000210011.
11001200010107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001200010107 - 212 = 11001200006011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11001200010091 and 11001200010100.
It is not a weakly prime, because it can be changed into another prime (11001200010187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500600005053 + 5500600005054.
It is an arithmetic number, because the mean of its divisors is an integer number (5500600005054).
Almost surely, 211001200010107 is an apocalyptic number.
11001200010107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001200010107 is an equidigital number, since it uses as much as digits as its factorization.
11001200010107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 11001200010107 its reverse (70101000210011), we get a palindrome (81102200220118).
The spelling of 11001200010107 in words is "eleven trillion, one billion, two hundred million, ten thousand, one hundred seven".
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