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11001200010107 is a prime number
BaseRepresentation
bin1010000000010110101010…
…0111100110001101111011
31102221201000112200111201012
42200011222213212031323
52420220424200310412
635221514223544135
72213544664123136
oct240055247461573
942851015614635
1011001200010107
1135616456722aa
12129813375b04b
1361a540c1ccc8
142a0664aa921d
15141276be7c22
hexa016a9e637b

11001200010107 has 2 divisors, whose sum is σ = 11001200010108. Its totient is φ = 11001200010106.

The previous prime is 11001200009959. The next prime is 11001200010113. The reversal of 11001200010107 is 70101000210011.

11001200010107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11001200010107 - 212 = 11001200006011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001200010091 and 11001200010100.

It is not a weakly prime, because it can be changed into another prime (11001200010187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500600005053 + 5500600005054.

It is an arithmetic number, because the mean of its divisors is an integer number (5500600005054).

Almost surely, 211001200010107 is an apocalyptic number.

11001200010107 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001200010107 is an equidigital number, since it uses as much as digits as its factorization.

11001200010107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14, while the sum is 14.

Adding to 11001200010107 its reverse (70101000210011), we get a palindrome (81102200220118).

The spelling of 11001200010107 in words is "eleven trillion, one billion, two hundred million, ten thousand, one hundred seven".