11001200010113 has 2 divisors, whose sum is σ = 11001200010114. Its totient is φ = 11001200010112.

The previous prime is 11001200010107. The next prime is 11001200010161. The reversal of 11001200010113 is 31101000210011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10423709444929 + 577490565184 = 3228577^2 + 759928^2 .

It is an emirp because it is prime and its reverse (31101000210011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001200010113 - 2³⁸ = 10726322103169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001200010094 and 11001200010103.

It is not a weakly prime, because it can be changed into another prime (11001200010313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500600005056 + 5500600005057.

It is an arithmetic number, because the mean of its divisors is an integer number (5500600005057).

Almost surely, 2^{11001200010113} is an apocalyptic number.

It is an amenable number.

11001200010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001200010113 is an equidigital number, since it uses as much as digits as its factorization.

11001200010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11001200010113 its reverse (31101000210011), we get a palindrome (42102200220124).

The spelling of 11001200010113 in words is "eleven trillion, one billion, two hundred million, ten thousand, one hundred thirteen".