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110012010193 is a prime number
BaseRepresentation
bin110011001110100111…
…0100000111011010001
3101111221221000011021001
41212131032200323101
53300301033311233
6122312215102001
710643125441411
oct1463516407321
9344857004231
10110012010193
1142723a03598
12193a2971901
13a4b2b43727
145478a2c641
152cdd1bb27d
hex199d3a0ed1

110012010193 has 2 divisors, whose sum is σ = 110012010194. Its totient is φ = 110012010192.

The previous prime is 110012010191. The next prime is 110012010239. The reversal of 110012010193 is 391010210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59723050689 + 50288959504 = 244383^2 + 224252^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012010193 - 21 = 110012010191 is a prime.

Together with 110012010191, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 110012010193.

It is not a weakly prime, because it can be changed into another prime (110012010191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006005096 + 55006005097.

It is an arithmetic number, because the mean of its divisors is an integer number (55006005097).

Almost surely, 2110012010193 is an apocalyptic number.

It is an amenable number.

110012010193 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012010193 is an equidigital number, since it uses as much as digits as its factorization.

110012010193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

The spelling of 110012010193 in words is "one hundred ten billion, twelve million, ten thousand, one hundred ninety-three".