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1100120200103 = 4349539946853
BaseRepresentation
bin10000000000100100010…
…001100001001110100111
310220011121021020120021102
4100000210101201032213
5121011021232400403
62201215505510315
7142324001261111
oct20004421411647
93804537216242
101100120200103
1139461619a121
1215926404239b
137c9829722b2
143b3634363b1
151d93b2e5b88
hex100244613a7

1100120200103 has 8 divisors (see below), whose sum is σ = 1100600460000. Its totient is φ = 1099640053408.

The previous prime is 1100120200063. The next prime is 1100120200117. The reversal of 1100120200103 is 3010020210011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100120200103 - 222 = 1100116005799 is a prime.

It is a super-2 number, since 2×11001202001032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100120205103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23456825 + ... + 23503677.

It is an arithmetic number, because the mean of its divisors is an integer number (137575057500).

Almost surely, 21100120200103 is an apocalyptic number.

1100120200103 is a deficient number, since it is larger than the sum of its proper divisors (480259897).

1100120200103 is an equidigital number, since it uses as much as digits as its factorization.

1100120200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56601.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 1100120200103 its reverse (3010020210011), we get a palindrome (4110140410114).

The spelling of 1100120200103 in words is "one trillion, one hundred billion, one hundred twenty million, two hundred thousand, one hundred three".

Divisors: 1 4349 5399 46853 23480251 203763697 252959347 1100120200103