Base | Representation |
---|---|
bin | 10000000000100100010… |
… | …001100001001101111111 |
3 | 10220011121021020120012221 |
4 | 100000210101201031333 |
5 | 121011021232400223 |
6 | 2201215505510211 |
7 | 142324001261023 |
oct | 20004421411577 |
9 | 3804537216187 |
10 | 1100120200063 |
11 | 39461619a095 |
12 | 159264042367 |
13 | 7c982972281 |
14 | 3b363436383 |
15 | 1d93b2e5b5d |
hex | 1002446137f |
1100120200063 has 2 divisors, whose sum is σ = 1100120200064. Its totient is φ = 1100120200062.
The previous prime is 1100120200051. The next prime is 1100120200117. The reversal of 1100120200063 is 3600020210011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100120200063 - 233 = 1091530265471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100120200013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550060100031 + 550060100032.
It is an arithmetic number, because the mean of its divisors is an integer number (550060100032).
Almost surely, 21100120200063 is an apocalyptic number.
1100120200063 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100120200063 is an equidigital number, since it uses as much as digits as its factorization.
1100120200063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1100120200063 its reverse (3600020210011), we get a palindrome (4700140410074).
The spelling of 1100120200063 in words is "one trillion, one hundred billion, one hundred twenty million, two hundred thousand, sixty-three".
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