1100120200117 has 2 divisors, whose sum is σ = 1100120200118. Its totient is φ = 1100120200116.

The previous prime is 1100120200063. The next prime is 1100120200139. The reversal of 1100120200117 is 7110020210011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1086318414756 + 13801785361 = 1042266^2 + 117481^2 .

It is an emirp because it is prime and its reverse (7110020210011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100120200117 is a prime.

It is a super-4 number, since 4×1100120200117⁴ (a number of 49 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1100120200117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100120200147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550060100058 + 550060100059.

It is an arithmetic number, because the mean of its divisors is an integer number (550060100059).

Almost surely, 2^{1100120200117} is an apocalyptic number.

It is an amenable number.

1100120200117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100120200117 is an equidigital number, since it uses as much as digits as its factorization.

1100120200117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 1100120200117 its reverse (7110020210011), we get a palindrome (8210140410128).

The spelling of 1100120200117 in words is "one trillion, one hundred billion, one hundred twenty million, two hundred thousand, one hundred seventeen".